12q^2+34q-28=

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Solution for 12q^2+34q-28= equation:


Simplifying
12q2 + 34q + -28 = 0

Reorder the terms:
-28 + 34q + 12q2 = 0

Solving
-28 + 34q + 12q2 = 0

Solving for variable 'q'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-14 + 17q + 6q2) = 0

Factor a trinomial.
2((-7 + -2q)(2 + -3q)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-7 + -2q)' equal to zero and attempt to solve: Simplifying -7 + -2q = 0 Solving -7 + -2q = 0 Move all terms containing q to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2q = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2q = 0 + 7 -2q = 0 + 7 Combine like terms: 0 + 7 = 7 -2q = 7 Divide each side by '-2'. q = -3.5 Simplifying q = -3.5

Subproblem 2

Set the factor '(2 + -3q)' equal to zero and attempt to solve: Simplifying 2 + -3q = 0 Solving 2 + -3q = 0 Move all terms containing q to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3q = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3q = 0 + -2 -3q = 0 + -2 Combine like terms: 0 + -2 = -2 -3q = -2 Divide each side by '-3'. q = 0.6666666667 Simplifying q = 0.6666666667

Solution

q = {-3.5, 0.6666666667}

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